Hartley will make his debut when Hyderabad hosts England’s three front-line spinners.

Hartley will make his debut when Hyderabad hosts England’s three front-line spinners.

In the first Test match of the series against India at the Rajiv Gandhi International Stadium in Hyderabad, left-arm spinner Tom Hartley will make his debut. The Lancashire spinner, 24, is a component of a three-pronged spin attack that will be spearheaded by Jack Leach, another left-arm spinner. Mark Wood is the only fast bowler in the starting eleven, with Rehan Ahmed as the legspinner.

With a poor average of 36.57, Hartley has 40 wickets from 20 first-class appearances. But in home Test matches, left-arm spin has proven to be somewhat of an Achilles heel for India, whose top order is primarily right-heavy. Should England require it, they can also rely on Joe Root’s off-spin abilities. The magical batter from England even claimed a five-fer during the most recent tour of India.

James Anderson, an experienced player, has no place in the starting lineup when a three-spinner approach is used. Furthermore, it is not a wholly original strategy in this region of the world. Australia achieved this with Todd Murphy and Scott Kuhnemann partnered with Nathan Lyon in the previous year. England also used three spinners during their previous tour. But the visitors had seam-bowling all-rounders Cameron Green and Ben Stokes as backup on both those occasions.

The other spinner in the team, Shoaib Bashir, has not yet left for India since he has not yet obtained a visa. To speed up the process, he reportedly took a plane from Abu Dhabi, where England’s squad was training, back to the UK.

Ben Foakes will take wickets, as captain Stokes has already stated, and Jonny Bairstow will play as a pure batsman at No. 5 in the lineup.

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